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4x^2+3x^2=700
We move all terms to the left:
4x^2+3x^2-(700)=0
We add all the numbers together, and all the variables
7x^2-700=0
a = 7; b = 0; c = -700;
Δ = b2-4ac
Δ = 02-4·7·(-700)
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{19600}=140$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-140}{2*7}=\frac{-140}{14} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+140}{2*7}=\frac{140}{14} =10 $
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